Optimal. Leaf size=198 \[ -\frac{B g^2 (b c-a d)^2 \text{PolyLog}\left (2,\frac{d (a+b x)}{b (c+d x)}\right )}{d^3 i}-\frac{g^2 (a+b x) (b c-a d) \left (2 B \log \left (\frac{e (a+b x)}{c+d x}\right )+2 A+B\right )}{2 d^2 i}-\frac{g^2 (b c-a d)^2 \log \left (\frac{b c-a d}{b (c+d x)}\right ) \left (2 B \log \left (\frac{e (a+b x)}{c+d x}\right )+2 A+3 B\right )}{2 d^3 i}+\frac{g^2 (a+b x)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{2 d i} \]
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Rubi [A] time = 0.487327, antiderivative size = 329, normalized size of antiderivative = 1.66, number of steps used = 19, number of rules used = 13, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.325, Rules used = {2528, 2486, 31, 2525, 12, 43, 2524, 2418, 2394, 2393, 2391, 2390, 2301} \[ -\frac{B g^2 (b c-a d)^2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{d^3 i}+\frac{g^2 (b c-a d)^2 \log (c i+d i x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d^3 i}+\frac{g^2 (a+b x)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{2 d i}-\frac{A b g^2 x (b c-a d)}{d^2 i}-\frac{B g^2 (a+b x) (b c-a d) \log \left (\frac{e (a+b x)}{c+d x}\right )}{d^2 i}-\frac{b B g^2 x (b c-a d)}{2 d^2 i}+\frac{B g^2 (b c-a d)^2 \log ^2(i (c+d x))}{2 d^3 i}+\frac{3 B g^2 (b c-a d)^2 \log (c+d x)}{2 d^3 i}-\frac{B g^2 (b c-a d)^2 \log (c i+d i x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{d^3 i} \]
Antiderivative was successfully verified.
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Rule 2528
Rule 2486
Rule 31
Rule 2525
Rule 12
Rule 43
Rule 2524
Rule 2418
Rule 2394
Rule 2393
Rule 2391
Rule 2390
Rule 2301
Rubi steps
\begin{align*} \int \frac{(a g+b g x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{32 c+32 d x} \, dx &=\int \left (-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{32 d^2}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{d^2 (32 c+32 d x)}+\frac{b g (a g+b g x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{32 d}\right ) \, dx\\ &=\frac{(b g) \int (a g+b g x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \, dx}{32 d}-\frac{\left (b (b c-a d) g^2\right ) \int \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \, dx}{32 d^2}+\frac{\left ((b c-a d)^2 g^2\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 c+32 d x} \, dx}{d^2}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}-\frac{B \int \frac{(b c-a d) g^2 (a+b x)}{c+d x} \, dx}{64 d}-\frac{\left (b B (b c-a d) g^2\right ) \int \log \left (\frac{e (a+b x)}{c+d x}\right ) \, dx}{32 d^2}-\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (32 c+32 d x)}{e (a+b x)} \, dx}{32 d^3}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}-\frac{\left (B (b c-a d) g^2\right ) \int \frac{a+b x}{c+d x} \, dx}{64 d}+\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{1}{c+d x} \, dx}{32 d^2}-\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (32 c+32 d x)}{a+b x} \, dx}{32 d^3 e}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{B (b c-a d)^2 g^2 \log (c+d x)}{32 d^3}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}-\frac{\left (B (b c-a d) g^2\right ) \int \left (\frac{b}{d}+\frac{-b c+a d}{d (c+d x)}\right ) \, dx}{64 d}-\frac{\left (B (b c-a d)^2 g^2\right ) \int \left (\frac{b e \log (32 c+32 d x)}{a+b x}-\frac{d e \log (32 c+32 d x)}{c+d x}\right ) \, dx}{32 d^3 e}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{b B (b c-a d) g^2 x}{64 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{3 B (b c-a d)^2 g^2 \log (c+d x)}{64 d^3}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}-\frac{\left (b B (b c-a d)^2 g^2\right ) \int \frac{\log (32 c+32 d x)}{a+b x} \, dx}{32 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{\log (32 c+32 d x)}{c+d x} \, dx}{32 d^2}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{b B (b c-a d) g^2 x}{64 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{3 B (b c-a d)^2 g^2 \log (c+d x)}{64 d^3}-\frac{B (b c-a d)^2 g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (32 c+32 d x)}{32 d^3}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \operatorname{Subst}\left (\int \frac{32 \log (x)}{x} \, dx,x,32 c+32 d x\right )}{1024 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{\log \left (\frac{32 d (a+b x)}{-32 b c+32 a d}\right )}{32 c+32 d x} \, dx}{d^2}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{b B (b c-a d) g^2 x}{64 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{3 B (b c-a d)^2 g^2 \log (c+d x)}{64 d^3}-\frac{B (b c-a d)^2 g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (32 c+32 d x)}{32 d^3}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,32 c+32 d x\right )}{32 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-32 b c+32 a d}\right )}{x} \, dx,x,32 c+32 d x\right )}{32 d^3}\\ &=-\frac{A b (b c-a d) g^2 x}{32 d^2}-\frac{b B (b c-a d) g^2 x}{64 d^2}-\frac{B (b c-a d) g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{32 d^2}+\frac{g^2 (a+b x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{64 d}+\frac{3 B (b c-a d)^2 g^2 \log (c+d x)}{64 d^3}+\frac{B (b c-a d)^2 g^2 \log ^2(32 (c+d x))}{64 d^3}-\frac{B (b c-a d)^2 g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (32 c+32 d x)}{32 d^3}+\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (32 c+32 d x)}{32 d^3}-\frac{B (b c-a d)^2 g^2 \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{32 d^3}\\ \end{align*}
Mathematica [A] time = 0.170747, size = 254, normalized size = 1.28 \[ \frac{g^2 \left (-B (b c-a d)^2 \left (2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+\log (i (c+d x)) \left (2 \log \left (\frac{d (a+b x)}{a d-b c}\right )-\log (i (c+d x))\right )\right )+d^2 (a+b x)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )+2 (b c-a d)^2 \log (i (c+d x)) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )-2 A b d x (b c-a d)+2 B d (a+b x) (a d-b c) \log \left (\frac{e (a+b x)}{c+d x}\right )+2 B (b c-a d)^2 \log (c+d x)-B (b c-a d) ((a d-b c) \log (c+d x)+b d x)\right )}{2 d^3 i} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.189, size = 2309, normalized size = 11.7 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.45319, size = 644, normalized size = 3.25 \begin{align*} 2 \, A a b g^{2}{\left (\frac{x}{d i} - \frac{c \log \left (d x + c\right )}{d^{2} i}\right )} + \frac{1}{2} \, A b^{2} g^{2}{\left (\frac{2 \, c^{2} \log \left (d x + c\right )}{d^{3} i} + \frac{d x^{2} - 2 \, c x}{d^{2} i}\right )} + \frac{A a^{2} g^{2} \log \left (d i x + c i\right )}{d i} + \frac{{\left (b^{2} c^{2} g^{2} - 2 \, a b c d g^{2} + a^{2} d^{2} g^{2}\right )}{\left (\log \left (b x + a\right ) \log \left (\frac{b d x + a d}{b c - a d} + 1\right ) +{\rm Li}_2\left (-\frac{b d x + a d}{b c - a d}\right )\right )} B}{d^{3} i} + \frac{{\left (2 \, a^{2} d^{2} g^{2} \log \left (e\right ) +{\left (2 \, g^{2} \log \left (e\right ) + 3 \, g^{2}\right )} b^{2} c^{2} - 4 \,{\left (g^{2} \log \left (e\right ) + g^{2}\right )} a b c d\right )} B \log \left (d x + c\right )}{2 \, d^{3} i} + \frac{B b^{2} d^{2} g^{2} x^{2} \log \left (e\right ) -{\left (b^{2} c^{2} g^{2} - 2 \, a b c d g^{2} + a^{2} d^{2} g^{2}\right )} B \log \left (d x + c\right )^{2} -{\left ({\left (2 \, g^{2} \log \left (e\right ) + g^{2}\right )} b^{2} c d -{\left (4 \, g^{2} \log \left (e\right ) + g^{2}\right )} a b d^{2}\right )} B x +{\left (B b^{2} d^{2} g^{2} x^{2} - 2 \,{\left (b^{2} c d g^{2} - 2 \, a b d^{2} g^{2}\right )} B x -{\left (2 \, a b c d g^{2} - 3 \, a^{2} d^{2} g^{2}\right )} B\right )} \log \left (b x + a\right ) -{\left (B b^{2} d^{2} g^{2} x^{2} - 2 \,{\left (b^{2} c d g^{2} - 2 \, a b d^{2} g^{2}\right )} B x\right )} \log \left (d x + c\right )}{2 \, d^{3} i} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{A b^{2} g^{2} x^{2} + 2 \, A a b g^{2} x + A a^{2} g^{2} +{\left (B b^{2} g^{2} x^{2} + 2 \, B a b g^{2} x + B a^{2} g^{2}\right )} \log \left (\frac{b e x + a e}{d x + c}\right )}{d i x + c i}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b g x + a g\right )}^{2}{\left (B \log \left (\frac{{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}}{d i x + c i}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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